Base | Representation |
---|---|
bin | 11011100011111111000001… |
… | …101010110011110111101011 |
3 | 120220012112021222021222121102 |
4 | 123203333001222303313223 |
5 | 111342032241433021303 |
6 | 1105451430022432015 |
7 | 34350602234350232 |
oct | 3343770152636753 |
9 | 526175258258542 |
10 | 121220111220203 |
11 | 35696184644746 |
12 | 11719329b9260b |
13 | 5284013460b78 |
14 | 21d1128551b19 |
15 | e0332ec2b288 |
hex | 6e3fc1ab3deb |
121220111220203 has 40 divisors (see below), whose sum is σ = 129269263174800. Its totient is φ = 113671303409664.
The previous prime is 121220111220199. The next prime is 121220111220217. The reversal of 121220111220203 is 302022111022121.
It is not a de Polignac number, because 121220111220203 - 22 = 121220111220199 is a prime.
It is a super-2 number, since 2×1212201112202032 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (121220111520203) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 35310254975 + ... + 35310258407.
It is an arithmetic number, because the mean of its divisors is an integer number (3231731579370).
Almost surely, 2121220111220203 is an apocalyptic number.
121220111220203 is a deficient number, since it is larger than the sum of its proper divisors (8049151954597).
121220111220203 is an frugal number, since it uses more digits than its factorization.
121220111220203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4929 (or 4878 counting only the distinct ones).
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 121220111220203 its reverse (302022111022121), we get a palindrome (423242222242324).
The spelling of 121220111220203 in words is "one hundred twenty-one trillion, two hundred twenty billion, one hundred eleven million, two hundred twenty thousand, two hundred three".
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