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12122513325035 = 512014931409397
BaseRepresentation
bin1011000001100111111000…
…0110011011101111101011
31120220220022210111212002022
42300121332012123233223
53042103401402400120
641441001123455055
72360552116052111
oct260317606335753
946826283455068
1012122513325035
113954146814253
12143951122748b
1369c1c04c0519
142dca38a43ab1
15160503885025
hexb067e19bbeb

12122513325035 has 16 divisors (see below), whose sum is σ = 14562116550432. Its totient is φ = 9687946944000.

The previous prime is 12122513325011. The next prime is 12122513325053. The reversal of 12122513325035 is 53052331522121.

It is not a de Polignac number, because 12122513325035 - 214 = 12122513308651 is a prime.

It is a super-2 number, since 2×121225133250352 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12122513324986 and 12122513325004.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 29405957 + ... + 29815353.

It is an arithmetic number, because the mean of its divisors is an integer number (910132284402).

Almost surely, 212122513325035 is an apocalyptic number.

12122513325035 is a deficient number, since it is larger than the sum of its proper divisors (2439603225397).

12122513325035 is a wasteful number, since it uses less digits than its factorization.

12122513325035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 415534.

The product of its (nonzero) digits is 54000, while the sum is 35.

Adding to 12122513325035 its reverse (53052331522121), we get a palindrome (65174844847156).

The spelling of 12122513325035 in words is "twelve trillion, one hundred twenty-two billion, five hundred thirteen million, three hundred twenty-five thousand, thirty-five".

Divisors: 1 5 1201 4931 6005 24655 409397 2046985 5922131 29610655 491685797 2018736607 2458428985 10093683035 2424502665007 12122513325035