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121232113003 = 314059386017
BaseRepresentation
bin111000011100111111…
…1110011110101101011
3102120220212121102210101
41300321333303311223
53441240410104003
6131405424530231
711521146646411
oct1607177636553
9376825542711
10121232113003
1147461404931
121b5b4480977
13b580543511
145c20c352b1
15324823611d
hex1c39ff3d6b

121232113003 has 4 divisors (see below), whose sum is σ = 121232813080. Its totient is φ = 121231412928.

The previous prime is 121232112943. The next prime is 121232113061. The reversal of 121232113003 is 300311232121.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 300311232121 = 577520470073.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-121232113003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (121232113063) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 121051 + ... + 507067.

It is an arithmetic number, because the mean of its divisors is an integer number (30308203270).

Almost surely, 2121232113003 is an apocalyptic number.

121232113003 is a deficient number, since it is larger than the sum of its proper divisors (700077).

121232113003 is an equidigital number, since it uses as much as digits as its factorization.

121232113003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 700076.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 121232113003 its reverse (300311232121), we get a palindrome (421543345124).

The spelling of 121232113003 in words is "one hundred twenty-one billion, two hundred thirty-two million, one hundred thirteen thousand, three".

Divisors: 1 314059 386017 121232113003