Base | Representation |
---|---|
bin | 1011000001101010011110… |
… | …1101011000101100011011 |
3 | 1120220222010110001211200010 |
4 | 2300122213231120230123 |
5 | 3042111314104331021 |
6 | 41441154302013003 |
7 | 2360605323444003 |
oct | 260324755305433 |
9 | 46828113054603 |
10 | 12123211402011 |
11 | 395447486a876 |
12 | 1439686b77163 |
13 | 69c2a2008518 |
14 | 2dcaa363b003 |
15 | 160544cc7976 |
hex | b06a7b58b1b |
12123211402011 has 4 divisors (see below), whose sum is σ = 16164281869352. Its totient is φ = 8082140934672.
The previous prime is 12123211402009. The next prime is 12123211402031. The reversal of 12123211402011 is 11020411232121.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 12123211402011 - 21 = 12123211402009 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12123211402031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2020535233666 + ... + 2020535233671.
It is an arithmetic number, because the mean of its divisors is an integer number (4041070467338).
Almost surely, 212123211402011 is an apocalyptic number.
12123211402011 is a deficient number, since it is larger than the sum of its proper divisors (4041070467341).
12123211402011 is an equidigital number, since it uses as much as digits as its factorization.
12123211402011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4041070467340.
The product of its (nonzero) digits is 192, while the sum is 21.
Adding to 12123211402011 its reverse (11020411232121), we get a palindrome (23143622634132).
The spelling of 12123211402011 in words is "twelve trillion, one hundred twenty-three billion, two hundred eleven million, four hundred two thousand, eleven".
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