Base | Representation |
---|---|
bin | 111000011100111111… |
… | …1111000010000111011 |
3 | 102120220212122100122210 |
4 | 1300321333320100323 |
5 | 3441240411144011 |
6 | 131405425150203 |
7 | 11521150053306 |
oct | 1607177702073 |
9 | 376825570583 |
10 | 121232131131 |
11 | 47461417511 |
12 | 1b5b448b363 |
13 | b58054b847 |
14 | 5c20c3bb3d |
15 | 324823b6a6 |
hex | 1c39ff843b |
121232131131 has 16 divisors (see below), whose sum is σ = 164310737024. Its totient is φ = 79491227904.
The previous prime is 121232131099. The next prime is 121232131151. The reversal of 121232131131 is 131131232121.
It is not a de Polignac number, because 121232131131 - 25 = 121232131099 is a prime.
It is a super-2 number, since 2×1212321311312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 121232131098 and 121232131107.
It is not an unprimeable number, because it can be changed into a prime (121232131151) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 339766 + ... + 598251.
It is an arithmetic number, because the mean of its divisors is an integer number (10269421064).
Almost surely, 2121232131131 is an apocalyptic number.
121232131131 is a deficient number, since it is larger than the sum of its proper divisors (43078605893).
121232131131 is an equidigital number, since it uses as much as digits as its factorization.
121232131131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 938730.
The product of its digits is 216, while the sum is 21.
Adding to 121232131131 its reverse (131131232121), we get a palindrome (252363363252).
The spelling of 121232131131 in words is "one hundred twenty-one billion, two hundred thirty-two million, one hundred thirty-one thousand, one hundred thirty-one".
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