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1212322013131 = 7489716186523
BaseRepresentation
bin10001101001000100000…
…001011101111111001011
311021220012210202020022011
4101221010001131333023
5124330313413410011
62324533312040351
7153405320041405
oct21510401357713
94256183666264
101212322013131
11428163197a19
12176b582330b7
138a424386b38
1442968c09b75
1521806867621
hex11a4405dfcb

1212322013131 has 4 divisors (see below), whose sum is σ = 1212338274552. Its totient is φ = 1212305751712.

The previous prime is 1212322013107. The next prime is 1212322013153. The reversal of 1212322013131 is 1313102232121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1212322013131 - 221 = 1212319915979 is a prime.

It is a super-2 number, since 2×12123220131312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1212322013731) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8018365 + ... + 8168158.

It is an arithmetic number, because the mean of its divisors is an integer number (303084568638).

Almost surely, 21212322013131 is an apocalyptic number.

1212322013131 is a deficient number, since it is larger than the sum of its proper divisors (16261421).

1212322013131 is an equidigital number, since it uses as much as digits as its factorization.

1212322013131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16261420.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 1212322013131 its reverse (1313102232121), we get a palindrome (2525424245252).

The spelling of 1212322013131 in words is "one trillion, two hundred twelve billion, three hundred twenty-two million, thirteen thousand, one hundred thirty-one".

Divisors: 1 74897 16186523 1212322013131