121233144441113 has 4 divisors (see below), whose sum is σ = 121234421924880. Its totient is φ = 121231866957348.

The previous prime is 121233144441043. The next prime is 121233144441133. The reversal of 121233144441113 is 311144441332121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 121233144441113 - 2¹² = 121233144437017 is a prime.

It is a super-2 number, since 2×121233144441113² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (121233144441133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 638599523 + ... + 638789336.

It is an arithmetic number, because the mean of its divisors is an integer number (30308605481220).

Almost surely, 2^{121233144441113} is an apocalyptic number.

It is an amenable number.

121233144441113 is a deficient number, since it is larger than the sum of its proper divisors (1277483767).

121233144441113 is an equidigital number, since it uses as much as digits as its factorization.

121233144441113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1277483766.

The product of its digits is 27648, while the sum is 35.

Adding to 121233144441113 its reverse (311144441332121), we get a palindrome (432377585773234).

The spelling of 121233144441113 in words is "one hundred twenty-one trillion, two hundred thirty-three billion, one hundred forty-four million, four hundred forty-one thousand, one hundred thirteen".