Base | Representation |
---|---|
bin | 1011000001101011101011… |
… | …1101101110101010011011 |
3 | 1120220222221221221112212111 |
4 | 2300122322331232222123 |
5 | 3042112444310002103 |
6 | 41441250322053151 |
7 | 2360616325361542 |
oct | 260327275565233 |
9 | 46828857845774 |
10 | 12123534453403 |
11 | 395462015909a |
12 | 14397571aa1b7 |
13 | 69c323c175a9 |
14 | 2dcad44d1159 |
15 | 16056333b86d |
hex | b06baf6ea9b |
12123534453403 has 4 divisors (see below), whose sum is σ = 12123642014848. Its totient is φ = 12123426891960.
The previous prime is 12123534453343. The next prime is 12123534453409. The reversal of 12123534453403 is 30435443532121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12123534453403 - 233 = 12114944518811 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12123534453409) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53611476 + ... + 53837137.
It is an arithmetic number, because the mean of its divisors is an integer number (3030910503712).
Almost surely, 212123534453403 is an apocalyptic number.
12123534453403 is a deficient number, since it is larger than the sum of its proper divisors (107561445).
12123534453403 is a wasteful number, since it uses less digits than its factorization.
12123534453403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 107561444.
The product of its (nonzero) digits is 518400, while the sum is 40.
Adding to 12123534453403 its reverse (30435443532121), we get a palindrome (42558977985524).
The spelling of 12123534453403 in words is "twelve trillion, one hundred twenty-three billion, five hundred thirty-four million, four hundred fifty-three thousand, four hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •