1212400403433 has 6 divisors (see below), whose sum is σ = 1751245027194. Its totient is φ = 808266935616.

The previous prime is 1212400403323. The next prime is 1212400403441. The reversal of 1212400403433 is 3343040042121.

1212400403433 is a `hidden beast` number, since 1 + 212 + 4 + 0 + 0 + 403 + 43 + 3 = 666.

It can be written as a sum of positive squares in only one way, i.e., 1144703128464 + 67697274969 = 1069908^2 + 260187^2 .

It is not a de Polignac number, because 1212400403433 - 2²⁰ = 1212399354857 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1212400403397 and 1212400403406.

It is not an unprimeable number, because it can be changed into a prime (1212400408433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 67355577960 + ... + 67355577977.

It is an arithmetic number, because the mean of its divisors is an integer number (291874171199).

Almost surely, 2^{1212400403433} is an apocalyptic number.

It is an amenable number.

1212400403433 is a deficient number, since it is larger than the sum of its proper divisors (538844623761).

1212400403433 is a wasteful number, since it uses less digits than its factorization.

1212400403433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 134711155943 (or 134711155940 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 1212400403433 its reverse (3343040042121), we get a palindrome (4555440445554).

The spelling of 1212400403433 in words is "one trillion, two hundred twelve billion, four hundred million, four hundred three thousand, four hundred thirty-three".