12124034113 has 4 divisors (see below), whose sum is σ = 12211257520. Its totient is φ = 12036810708.

The previous prime is 12124034101. The next prime is 12124034123. The reversal of 12124034113 is 31143042121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12124034113 - 2²¹ = 12121936961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12124034123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43611495 + ... + 43611772.

It is an arithmetic number, because the mean of its divisors is an integer number (3052814380).

Almost surely, 2^12124034113 is an apocalyptic number.

It is an amenable number.

12124034113 is a deficient number, since it is larger than the sum of its proper divisors (87223407).

12124034113 is an equidigital number, since it uses as much as digits as its factorization.

12124034113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 87223406.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 12124034113 its reverse (31143042121), we get a palindrome (43267076234).

The spelling of 12124034113 in words is "twelve billion, one hundred twenty-four million, thirty-four thousand, one hundred thirteen".