Base | Representation |
---|---|
bin | 111000011101010011… |
… | …0101101111011110001 |
3 | 102120221120210121210001 |
4 | 1300322212231323301 |
5 | 3441301012444213 |
6 | 131410431310001 |
7 | 11521332436354 |
oct | 1607246557361 |
9 | 376846717701 |
10 | 121242312433 |
11 | 47467140910 |
12 | 1b5b797b301 |
13 | b5826a4a98 |
14 | 5c2232c29b |
15 | 324909d1dd |
hex | 1c3a9adef1 |
121242312433 has 4 divisors (see below), whose sum is σ = 132264340848. Its totient is φ = 110220284020.
The previous prime is 121242312407. The next prime is 121242312439. The reversal of 121242312433 is 334213242121.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 121242312433 - 29 = 121242311921 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (121242312439) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5511014191 + ... + 5511014212.
It is an arithmetic number, because the mean of its divisors is an integer number (33066085212).
Almost surely, 2121242312433 is an apocalyptic number.
It is an amenable number.
121242312433 is a deficient number, since it is larger than the sum of its proper divisors (11022028415).
121242312433 is a wasteful number, since it uses less digits than its factorization.
121242312433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11022028414.
The product of its digits is 6912, while the sum is 28.
Adding to 121242312433 its reverse (334213242121), we get a palindrome (455455554554).
The spelling of 121242312433 in words is "one hundred twenty-one billion, two hundred forty-two million, three hundred twelve thousand, four hundred thirty-three".
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