12125050033 has 4 divisors (see below), whose sum is σ = 12125370880. Its totient is φ = 12124729188.

The previous prime is 12125050009. The next prime is 12125050061. The reversal of 12125050033 is 33005052121.

12125050033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33005052121 = 1277 ⋅25845773.

It is a cyclic number.

It is not a de Polignac number, because 12125050033 - 2²⁵ = 12091495601 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12125049986 and 12125050013.

It is not an unprimeable number, because it can be changed into a prime (12125050633) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94785 + ... + 182302.

It is an arithmetic number, because the mean of its divisors is an integer number (3031342720).

Almost surely, 2^12125050033 is an apocalyptic number.

It is an amenable number.

12125050033 is a deficient number, since it is larger than the sum of its proper divisors (320847).

12125050033 is an equidigital number, since it uses as much as digits as its factorization.

12125050033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 320846.

The product of its (nonzero) digits is 900, while the sum is 22.

The spelling of 12125050033 in words is "twelve billion, one hundred twenty-five million, fifty thousand, thirty-three".