121300000033 has 4 divisors (see below), whose sum is σ = 122412844180. Its totient is φ = 120187155888.

The previous prime is 121300000027. The next prime is 121300000039. The reversal of 121300000033 is 330000003121.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 330000003121 = 31 ⋅10645161391.

It is an interprime number because it is at equal distance from previous prime (121300000027) and next prime (121300000039).

It can be written as a sum of positive squares in 2 ways, for example, as 41102291169 + 80197708864 = 202737^2 + 283192^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-121300000033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 121299999959 and 121300000022.

It is not an unprimeable number, because it can be changed into a prime (121300000039) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 556421910 + ... + 556422127.

It is an arithmetic number, because the mean of its divisors is an integer number (30603211045).

Almost surely, 2^121300000033 is an apocalyptic number.

It is an amenable number.

121300000033 is a deficient number, since it is larger than the sum of its proper divisors (1112844147).

121300000033 is a wasteful number, since it uses less digits than its factorization.

121300000033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1112844146.

The product of its (nonzero) digits is 54, while the sum is 13.

Adding to 121300000033 its reverse (330000003121), we get a palindrome (451300003154).

The spelling of 121300000033 in words is "one hundred twenty-one billion, three hundred million, thirty-three", and thus it is an aban number.