Base | Representation |
---|---|
bin | 11011100101001010011110… |
… | …111001010100100100010011 |
3 | 120220111021102110120012212202 |
4 | 123211022132321110210103 |
5 | 111344344204320401321 |
6 | 1105552545411313415 |
7 | 34356501064333025 |
oct | 3345123671244423 |
9 | 526437373505782 |
10 | 121301132200211 |
11 | 357175808a4157 |
12 | 11730b7b8ab86b |
13 | 528b855c6a362 |
14 | 21d5012b3a015 |
15 | e054c2b7270b |
hex | 6e529ee54913 |
121301132200211 has 4 divisors (see below), whose sum is σ = 121301662806792. Its totient is φ = 121300601593632.
The previous prime is 121301132200201. The next prime is 121301132200247. The reversal of 121301132200211 is 112002231103121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 121301132200211 - 26 = 121301132200147 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (121301132200201) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 264960230 + ... + 265417643.
It is an arithmetic number, because the mean of its divisors is an integer number (30325415701698).
Almost surely, 2121301132200211 is an apocalyptic number.
121301132200211 is a deficient number, since it is larger than the sum of its proper divisors (530606581).
121301132200211 is an equidigital number, since it uses as much as digits as its factorization.
121301132200211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 530606580.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 121301132200211 its reverse (112002231103121), we get a palindrome (233303363303332).
The spelling of 121301132200211 in words is "one hundred twenty-one trillion, three hundred one billion, one hundred thirty-two million, two hundred thousand, two hundred eleven".
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