12130113433 has 8 divisors (see below), whose sum is σ = 12328256520. Its totient is φ = 11933500800.

The previous prime is 12130113431. The next prime is 12130113439. The reversal of 12130113433 is 33431103121.

12130113433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 4 ways, for example, as 3766645129 + 8363468304 = 61373^2 + 91452^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12130113433 - 2¹ = 12130113431 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12130113431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 366628 + ... + 398341.

It is an arithmetic number, because the mean of its divisors is an integer number (1541032065).

Almost surely, 2^12130113433 is an apocalyptic number.

It is an amenable number.

12130113433 is a deficient number, since it is larger than the sum of its proper divisors (198143087).

12130113433 is a wasteful number, since it uses less digits than its factorization.

12130113433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 765227.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 12130113433 its reverse (33431103121), we get a palindrome (45561216554).

The spelling of 12130113433 in words is "twelve billion, one hundred thirty million, one hundred thirteen thousand, four hundred thirty-three".