Base | Representation |
---|---|
bin | 1011000010000100010001… |
… | …0001001110111010011001 |
3 | 1120221121222211022001202010 |
4 | 2300201010101032322121 |
5 | 3042220003022341441 |
6 | 41444301200100133 |
7 | 2361242001244215 |
oct | 260410421167231 |
9 | 46847884261663 |
10 | 12130133012121 |
11 | 39573a6942a03 |
12 | 143aa99004649 |
13 | 69cb35cc5bc7 |
14 | 2dd15c9cd945 |
15 | 1607ec7aa116 |
hex | b084444ee99 |
12130133012121 has 4 divisors (see below), whose sum is σ = 16173510682832. Its totient is φ = 8086755341412.
The previous prime is 12130133012093. The next prime is 12130133012141. The reversal of 12130133012121 is 12121033103121.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 12130133012121 - 219 = 12130132487833 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12130133012141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2021688835351 + ... + 2021688835356.
It is an arithmetic number, because the mean of its divisors is an integer number (4043377670708).
Almost surely, 212130133012121 is an apocalyptic number.
It is an amenable number.
12130133012121 is a deficient number, since it is larger than the sum of its proper divisors (4043377670711).
12130133012121 is an equidigital number, since it uses as much as digits as its factorization.
12130133012121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4043377670710.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 12130133012121 its reverse (12121033103121), we get a palindrome (24251166115242).
The spelling of 12130133012121 in words is "twelve trillion, one hundred thirty billion, one hundred thirty-three million, twelve thousand, one hundred twenty-one".
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