12130423113 has 4 divisors (see below), whose sum is σ = 16173897488. Its totient is φ = 8086948740.

The previous prime is 12130423087. The next prime is 12130423147. The reversal of 12130423113 is 31132403121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a de Polignac number, because none of the positive numbers 2^k-12130423113 is a prime.

It is a super-2 number, since 2×12130423113² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 12130423113.

It is not an unprimeable number, because it can be changed into a prime (12130423013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2021737183 + ... + 2021737188.

It is an arithmetic number, because the mean of its divisors is an integer number (4043474372).

Almost surely, 2^12130423113 is an apocalyptic number.

It is an amenable number.

12130423113 is a deficient number, since it is larger than the sum of its proper divisors (4043474375).

12130423113 is an equidigital number, since it uses as much as digits as its factorization.

12130423113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4043474374.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 12130423113 its reverse (31132403121), we get a palindrome (43262826234).

The spelling of 12130423113 in words is "twelve billion, one hundred thirty million, four hundred twenty-three thousand, one hundred thirteen".