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1213042433 = 10373316067
BaseRepresentation
bin100100001001101…
…1000111100000001
310010112112221101112
41020103120330001
54441014324213
6320211413105
742026455601
oct11023307401
93115487345
101213042433
11572804809
1229a2b4195
1316440cab5
14b7166c01
1571764ea8
hex484d8f01

1213042433 has 8 divisors (see below), whose sum is σ = 1226566848. Its totient is φ = 1199551824.

The previous prime is 1213042423. The next prime is 1213042477. The reversal of 1213042433 is 3342403121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1213042433 - 24 = 1213042417 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1213042399 and 1213042408.

It is not an unprimeable number, because it can be changed into a prime (1213042423) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 67466 + ... + 83532.

It is an arithmetic number, because the mean of its divisors is an integer number (153320856).

Almost surely, 21213042433 is an apocalyptic number.

It is an amenable number.

1213042433 is a deficient number, since it is larger than the sum of its proper divisors (13524415).

1213042433 is a wasteful number, since it uses less digits than its factorization.

1213042433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16903.

The product of its (nonzero) digits is 1728, while the sum is 23.

The square root of 1213042433 is about 34828.7587059889. The cubic root of 1213042433 is about 1066.4946086519.

Adding to 1213042433 its reverse (3342403121), we get a palindrome (4555445554).

The spelling of 1213042433 in words is "one billion, two hundred thirteen million, forty-two thousand, four hundred thirty-three".

Divisors: 1 103 733 16067 75499 1654901 11777111 1213042433