Base | Representation |
---|---|
bin | 10110100110001000… |
… | …01000101101001011 |
3 | 1011022102122020012122 |
4 | 23103010020231023 |
5 | 144321014331103 |
6 | 5323425401455 |
7 | 606421616120 |
oct | 132304105513 |
9 | 34272566178 |
10 | 12131011403 |
11 | 5165704465 |
12 | 242679928b |
13 | 11b4345774 |
14 | 8311a2747 |
15 | 4aeeedb38 |
hex | 2d3108b4b |
12131011403 has 8 divisors (see below), whose sum is σ = 13917960672. Its totient is φ = 10357549056.
The previous prime is 12131011367. The next prime is 12131011423. The reversal of 12131011403 is 30411013121.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12131011403 - 218 = 12130749259 is a prime.
It is a super-2 number, since 2×121310114032 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (12131011423) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3369800 + ... + 3373397.
It is an arithmetic number, because the mean of its divisors is an integer number (1739745084).
Almost surely, 212131011403 is an apocalyptic number.
12131011403 is a deficient number, since it is larger than the sum of its proper divisors (1786949269).
12131011403 is an equidigital number, since it uses as much as digits as its factorization.
12131011403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6743461.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 12131011403 its reverse (30411013121), we get a palindrome (42542024524).
The spelling of 12131011403 in words is "twelve billion, one hundred thirty-one million, eleven thousand, four hundred three".
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