1213111212113 has 4 divisors (see below), whose sum is σ = 1213127834688. Its totient is φ = 1213094589540.

The previous prime is 1213111212107. The next prime is 1213111212119. The reversal of 1213111212113 is 3112121113121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (1213111212107) and next prime (1213111212119).

It is a cyclic number.

It is not a de Polignac number, because 1213111212113 - 2⁸ = 1213111211857 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1213111212119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8201333 + ... + 8347938.

It is an arithmetic number, because the mean of its divisors is an integer number (303281958672).

Almost surely, 2^{1213111212113} is an apocalyptic number.

It is an amenable number.

1213111212113 is a deficient number, since it is larger than the sum of its proper divisors (16622575).

1213111212113 is an equidigital number, since it uses as much as digits as its factorization.

1213111212113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16622574.

The product of its digits is 72, while the sum is 20.

Adding to 1213111212113 its reverse (3112121113121), we get a palindrome (4325232325234).

The spelling of 1213111212113 in words is "one trillion, two hundred thirteen billion, one hundred eleven million, two hundred twelve thousand, one hundred thirteen".