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12132113 = 71733159
BaseRepresentation
bin101110010001…
…111100010001
3211211101010112
4232101330101
511101211423
61112011105
7205056410
oct56217421
924741115
1012132113
116937044
124090a95
13268a186
14187b477
1510e9a78
hexb91f11

12132113 has 4 divisors (see below), whose sum is σ = 13865280. Its totient is φ = 10398948.

The previous prime is 12132103. The next prime is 12132151. The reversal of 12132113 is 31123121.

12132113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31123121 = 191638059.

It is not a de Polignac number, because 12132113 - 24 = 12132097 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12132103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 866573 + ... + 866586.

It is an arithmetic number, because the mean of its divisors is an integer number (3466320).

Almost surely, 212132113 is an apocalyptic number.

It is an amenable number.

12132113 is a deficient number, since it is larger than the sum of its proper divisors (1733167).

12132113 is an equidigital number, since it uses as much as digits as its factorization.

12132113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1733166.

The product of its digits is 36, while the sum is 14.

The square root of 12132113 is about 3483.1182868229. The cubic root of 12132113 is about 229.7799596875.

Adding to 12132113 its reverse (31123121), we get a palindrome (43255234).

The spelling of 12132113 in words is "twelve million, one hundred thirty-two thousand, one hundred thirteen".

Divisors: 1 7 1733159 12132113