121322313443433 has 4 divisors (see below), whose sum is σ = 161763084591248. Its totient is φ = 80881542295620.

The previous prime is 121322313443423. The next prime is 121322313443489. The reversal of 121322313443433 is 334344313223121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 121322313443433 - 2¹⁰ = 121322313442409 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 121322313443391 and 121322313443400.

It is not an unprimeable number, because it can be changed into a prime (121322313443423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20220385573903 + ... + 20220385573908.

It is an arithmetic number, because the mean of its divisors is an integer number (40440771147812).

Almost surely, 2^{121322313443433} is an apocalyptic number.

It is an amenable number.

121322313443433 is a deficient number, since it is larger than the sum of its proper divisors (40440771147815).

121322313443433 is an equidigital number, since it uses as much as digits as its factorization.

121322313443433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40440771147814.

The product of its digits is 373248, while the sum is 39.

Adding to 121322313443433 its reverse (334344313223121), we get a palindrome (455666626666554).

The spelling of 121322313443433 in words is "one hundred twenty-one trillion, three hundred twenty-two billion, three hundred thirteen million, four hundred forty-three thousand, four hundred thirty-three".