Base | Representation |
---|---|
bin | 10001101001111010111… |
… | …110101011110100100011 |
3 | 11021222121001200120000002 |
4 | 101221322332223310203 |
5 | 124334210432431433 |
6 | 2325205010050215 |
7 | 153440214050060 |
oct | 21517276536443 |
9 | 4258531616002 |
10 | 1213244030243 |
11 | 428596698033 |
12 | 177174b7996b |
13 | 8a5403bbaab |
14 | 42a15457c67 |
15 | 2185c7929e8 |
hex | 11a7afabd23 |
1213244030243 has 4 divisors (see below), whose sum is σ = 1386564606000. Its totient is φ = 1039923454488.
The previous prime is 1213244030239. The next prime is 1213244030279. The reversal of 1213244030243 is 3420304423121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1213244030243 - 22 = 1213244030239 is a prime.
It is a super-2 number, since 2×12132440302432 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1213244030203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 86660287868 + ... + 86660287881.
It is an arithmetic number, because the mean of its divisors is an integer number (346641151500).
Almost surely, 21213244030243 is an apocalyptic number.
1213244030243 is a deficient number, since it is larger than the sum of its proper divisors (173320575757).
1213244030243 is an equidigital number, since it uses as much as digits as its factorization.
1213244030243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 173320575756.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 1213244030243 its reverse (3420304423121), we get a palindrome (4633548453364).
The spelling of 1213244030243 in words is "one trillion, two hundred thirteen billion, two hundred forty-four million, thirty thousand, two hundred forty-three".
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