Base | Representation |
---|---|
bin | 10110100110010011… |
… | …01001010010000001 |
3 | 1011022112100121012200 |
4 | 23103021221102001 |
5 | 144321402034203 |
6 | 5323520343413 |
7 | 606440112351 |
oct | 132311512201 |
9 | 34275317180 |
10 | 12132455553 |
11 | 5166500479 |
12 | 2427174b69 |
13 | 11b472cbaa |
14 | 83145ab61 |
15 | 4b01d69a3 |
hex | 2d3269481 |
12132455553 has 6 divisors (see below), whose sum is σ = 17524658034. Its totient is φ = 8088303696.
The previous prime is 12132455537. The next prime is 12132455561. The reversal of 12132455553 is 35555423121.
12132455553 is a `hidden beast` number, since 1 + 21 + 32 + 4 + 55 + 553 = 666.
It can be written as a sum of positive squares in only one way, i.e., 10638478449 + 1493977104 = 103143^2 + 38652^2 .
It is not a de Polignac number, because 12132455553 - 24 = 12132455537 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12132455513) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 674025300 + ... + 674025317.
It is an arithmetic number, because the mean of its divisors is an integer number (2920776339).
Almost surely, 212132455553 is an apocalyptic number.
It is an amenable number.
12132455553 is a deficient number, since it is larger than the sum of its proper divisors (5392202481).
12132455553 is a wasteful number, since it uses less digits than its factorization.
12132455553 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1348050623 (or 1348050620 counting only the distinct ones).
The product of its digits is 90000, while the sum is 36.
Adding to 12132455553 its reverse (35555423121), we get a palindrome (47687878674).
The spelling of 12132455553 in words is "twelve billion, one hundred thirty-two million, four hundred fifty-five thousand, five hundred fifty-three".
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