Base | Representation |
---|---|
bin | 111000100000000000… |
… | …1000101010011110001 |
3 | 102121011220122121121221 |
4 | 1301000001011103301 |
5 | 3441442234010001 |
6 | 131423433345041 |
7 | 11523514263325 |
oct | 1610001052361 |
9 | 377156577557 |
10 | 121333110001 |
11 | 47503417424 |
12 | 1b622268181 |
13 | b598445a5c |
14 | 5c30405985 |
15 | 32520361a1 |
hex | 1c400454f1 |
121333110001 has 4 divisors (see below), whose sum is σ = 121431675904. Its totient is φ = 121234544100.
The previous prime is 121333109939. The next prime is 121333110029. The reversal of 121333110001 is 100011333121.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 121333110001 - 225 = 121299555569 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (121333110071) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49281105 + ... + 49283566.
It is an arithmetic number, because the mean of its divisors is an integer number (30357918976).
Almost surely, 2121333110001 is an apocalyptic number.
It is an amenable number.
121333110001 is a deficient number, since it is larger than the sum of its proper divisors (98565903).
121333110001 is an equidigital number, since it uses as much as digits as its factorization.
121333110001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 98565902.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 121333110001 its reverse (100011333121), we get a palindrome (221344443122).
The spelling of 121333110001 in words is "one hundred twenty-one billion, three hundred thirty-three million, one hundred ten thousand, one".
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