Base | Representation |
---|---|
bin | 10001101010000011011… |
… | …101001111100000010011 |
3 | 11021222221222022111102111 |
4 | 101222003131033200103 |
5 | 124340003340232301 |
6 | 2325231050330151 |
7 | 153443562010423 |
oct | 21520335174023 |
9 | 4258858274374 |
10 | 1213386258451 |
11 | 428659a01204 |
12 | 1771b4729957 |
13 | 8a5639c93b3 |
14 | 42a2a2bc483 |
15 | 21869ed9551 |
hex | 11a8374f813 |
1213386258451 has 4 divisors (see below), whose sum is σ = 1218220466904. Its totient is φ = 1208552050000.
The previous prime is 1213386258449. The next prime is 1213386258481. The reversal of 1213386258451 is 1548526833121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1213386258451 - 21 = 1213386258449 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1213386258395 and 1213386258404.
It is not an unprimeable number, because it can be changed into a prime (1213386258481) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2417103850 + ... + 2417104351.
It is an arithmetic number, because the mean of its divisors is an integer number (304555116726).
Almost surely, 21213386258451 is an apocalyptic number.
1213386258451 is a deficient number, since it is larger than the sum of its proper divisors (4834208453).
1213386258451 is an equidigital number, since it uses as much as digits as its factorization.
1213386258451 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4834208452.
The product of its digits is 1382400, while the sum is 49.
The spelling of 1213386258451 in words is "one trillion, two hundred thirteen billion, three hundred eighty-six million, two hundred fifty-eight thousand, four hundred fifty-one".
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