Base | Representation |
---|---|
bin | 10001101010000100010… |
… | …111001000110110100011 |
3 | 11022000000000212120111110 |
4 | 101222010113020312203 |
5 | 124340021231414210 |
6 | 2325232351514403 |
7 | 153444135011511 |
oct | 21520427106643 |
9 | 4260000776443 |
10 | 1213401435555 |
11 | 428667527a71 |
12 | 1771b9828a03 |
13 | 8a566bb152a |
14 | 42a2c30d4b1 |
15 | 2186b4d6420 |
hex | 11a845c8da3 |
1213401435555 has 16 divisors (see below), whose sum is σ = 1963256257440. Its totient is φ = 639876112128.
The previous prime is 1213401435553. The next prime is 1213401435559. The reversal of 1213401435555 is 5555341043121.
It is not a de Polignac number, because 1213401435555 - 21 = 1213401435553 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1213401435553) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 454456132 + ... + 454458801.
It is an arithmetic number, because the mean of its divisors is an integer number (122703516090).
Almost surely, 21213401435555 is an apocalyptic number.
1213401435555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1213401435555 is a deficient number, since it is larger than the sum of its proper divisors (749854821885).
1213401435555 is an equidigital number, since it uses as much as digits as its factorization.
1213401435555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 908915030.
The product of its (nonzero) digits is 180000, while the sum is 39.
Adding to 1213401435555 its reverse (5555341043121), we get a palindrome (6768742478676).
The spelling of 1213401435555 in words is "one trillion, two hundred thirteen billion, four hundred one million, four hundred thirty-five thousand, five hundred fifty-five".
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