1213403424131 has 4 divisors (see below), whose sum is σ = 1213599045912. Its totient is φ = 1213207802352.

The previous prime is 1213403424113. The next prime is 1213403424139. The reversal of 1213403424131 is 1314243043121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1213403424131 - 2⁶ = 1213403424067 is a prime.

It is a super-2 number, since 2×1213403424131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1213403424094 and 1213403424103.

It is not an unprimeable number, because it can be changed into a prime (1213403424139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 97801586 + ... + 97813991.

It is an arithmetic number, because the mean of its divisors is an integer number (303399761478).

Almost surely, 2^{1213403424131} is an apocalyptic number.

1213403424131 is a deficient number, since it is larger than the sum of its proper divisors (195621781).

1213403424131 is an equidigital number, since it uses as much as digits as its factorization.

1213403424131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 195621780.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1213403424131 its reverse (1314243043121), we get a palindrome (2527646467252).

The spelling of 1213403424131 in words is "one trillion, two hundred thirteen billion, four hundred three million, four hundred twenty-four thousand, one hundred thirty-one".