1213404353113 has 4 divisors (see below), whose sum is σ = 1214871590160. Its totient is φ = 1211937116068.

The previous prime is 1213404353099. The next prime is 1213404353123. The reversal of 1213404353113 is 3113534043121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1213404353113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1213404353123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 733617283 + ... + 733618936.

It is an arithmetic number, because the mean of its divisors is an integer number (303717897540).

Almost surely, 2^{1213404353113} is an apocalyptic number.

It is an amenable number.

1213404353113 is a deficient number, since it is larger than the sum of its proper divisors (1467237047).

1213404353113 is an equidigital number, since it uses as much as digits as its factorization.

1213404353113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1467237046.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 1213404353113 its reverse (3113534043121), we get a palindrome (4326938396234).

The spelling of 1213404353113 in words is "one trillion, two hundred thirteen billion, four hundred four million, three hundred fifty-three thousand, one hundred thirteen".