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12134054153 = 132103697079
BaseRepresentation
bin10110100110011111…
…01111100100001001
31011022122100211002002
423103033233210021
5144322304213103
65324014520345
7606456521114
oct132317574411
934278324062
1012134054153
1151673a2531
1224278060b5
1311b4b6c700
1483175557b
154b0400488
hex2d33ef909

12134054153 has 12 divisors (see below), whose sum is σ = 13266826560. Its totient is φ = 11091905136.

The previous prime is 12134054129. The next prime is 12134054159. The reversal of 12134054153 is 35145043121.

It is not a de Polignac number, because 12134054153 - 212 = 12134050057 is a prime.

It is not an unprimeable number, because it can be changed into a prime (12134054159) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 331133 + ... + 365946.

It is an arithmetic number, because the mean of its divisors is an integer number (1105568880).

Almost surely, 212134054153 is an apocalyptic number.

12134054153 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

12134054153 is a deficient number, since it is larger than the sum of its proper divisors (1132772407).

12134054153 is a wasteful number, since it uses less digits than its factorization.

12134054153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 697208 (or 697195 counting only the distinct ones).

The product of its (nonzero) digits is 7200, while the sum is 29.

Adding to 12134054153 its reverse (35145043121), we get a palindrome (47279097274).

The spelling of 12134054153 in words is "twelve billion, one hundred thirty-four million, fifty-four thousand, one hundred fifty-three".

Divisors: 1 13 103 169 1339 17407 697079 9062027 71799137 117806351 933388781 12134054153