1213414541041 has 4 divisors (see below), whose sum is σ = 1213891702272. Its totient is φ = 1212937379812.

The previous prime is 1213414541039. The next prime is 1213414541107. The reversal of 1213414541041 is 1401454143121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1213414541041 - 2¹ = 1213414541039 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1213414540994 and 1213414541012.

It is not an unprimeable number, because it can be changed into a prime (1213414541021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 238576801 + ... + 238581886.

It is an arithmetic number, because the mean of its divisors is an integer number (303472925568).

Almost surely, 2^{1213414541041} is an apocalyptic number.

It is an amenable number.

1213414541041 is a deficient number, since it is larger than the sum of its proper divisors (477161231).

1213414541041 is an equidigital number, since it uses as much as digits as its factorization.

1213414541041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 477161230.

The product of its (nonzero) digits is 7680, while the sum is 31.

Adding to 1213414541041 its reverse (1401454143121), we get a palindrome (2614868684162).

The spelling of 1213414541041 in words is "one trillion, two hundred thirteen billion, four hundred fourteen million, five hundred forty-one thousand, forty-one".