1213444312033 has 4 divisors (see below), whose sum is σ = 1277309802160. Its totient is φ = 1149578821908.

The previous prime is 1213444312021. The next prime is 1213444312049. The reversal of 1213444312033 is 3302134443121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1213444312033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1213444311986 and 1213444312004.

It is not an unprimeable number, because it can be changed into a prime (1213444312013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31932745035 + ... + 31932745072.

It is an arithmetic number, because the mean of its divisors is an integer number (319327450540).

Almost surely, 2^{1213444312033} is an apocalyptic number.

It is an amenable number.

1213444312033 is a deficient number, since it is larger than the sum of its proper divisors (63865490127).

1213444312033 is an equidigital number, since it uses as much as digits as its factorization.

1213444312033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 63865490126.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 1213444312033 its reverse (3302134443121), we get a palindrome (4515578755154).

The spelling of 1213444312033 in words is "one trillion, two hundred thirteen billion, four hundred forty-four million, three hundred twelve thousand, thirty-three".