121401224433 has 6 divisors (see below), whose sum is σ = 175357324194. Its totient is φ = 80934149616.

The previous prime is 121401224429. The next prime is 121401224443. The reversal of 121401224433 is 334422104121.

121401224433 is a `hidden beast` number, since 1 + 2 + 1 + 4 + 0 + 1 + 224 + 433 = 666.

It can be written as a sum of positive squares in only one way, i.e., 103559745249 + 17841479184 = 321807^2 + 133572^2 .

It is not a de Polignac number, because 121401224433 - 2² = 121401224429 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 121401224397 and 121401224406.

It is not an unprimeable number, because it can be changed into a prime (121401224443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 6744512460 + ... + 6744512477.

It is an arithmetic number, because the mean of its divisors is an integer number (29226220699).

Almost surely, 2^121401224433 is an apocalyptic number.

It is an amenable number.

121401224433 is a deficient number, since it is larger than the sum of its proper divisors (53956099761).

121401224433 is a wasteful number, since it uses less digits than its factorization.

121401224433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13489024943 (or 13489024940 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 27.

Adding to 121401224433 its reverse (334422104121), we get a palindrome (455823328554).

The spelling of 121401224433 in words is "one hundred twenty-one billion, four hundred one million, two hundred twenty-four thousand, four hundred thirty-three".