1214025403 has 4 divisors (see below), whose sum is σ = 1285438680. Its totient is φ = 1142612128.

The previous prime is 1214025383. The next prime is 1214025419. The reversal of 1214025403 is 3045204121.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3045204121 = 31 ⋅98232391.

It is a cyclic number.

It is not a de Polignac number, because 1214025403 - 2²¹ = 1211928251 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1214065403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35706613 + ... + 35706646.

It is an arithmetic number, because the mean of its divisors is an integer number (321359670).

Almost surely, 2^1214025403 is an apocalyptic number.

1214025403 is a deficient number, since it is larger than the sum of its proper divisors (71413277).

1214025403 is an equidigital number, since it uses as much as digits as its factorization.

1214025403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 71413276.

The product of its (nonzero) digits is 960, while the sum is 22.

The square root of 1214025403 is about 34842.8673188646. The cubic root of 1214025403 is about 1066.7826032946.

Adding to 1214025403 its reverse (3045204121), we get a palindrome (4259229524).

The spelling of 1214025403 in words is "one billion, two hundred fourteen million, twenty-five thousand, four hundred three".