1214030133035 has 4 divisors (see below), whose sum is σ = 1456836159648. Its totient is φ = 971224106424.

The previous prime is 1214030133013. The next prime is 1214030133079. The reversal of 1214030133035 is 5303310304121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1214030133035 - 2²² = 1214025938731 is a prime.

It is a super-2 number, since 2×1214030133035² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1214030132995 and 1214030133013.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 121403013299 + ... + 121403013308.

It is an arithmetic number, because the mean of its divisors is an integer number (364209039912).

Almost surely, 2^{1214030133035} is an apocalyptic number.

1214030133035 is a deficient number, since it is larger than the sum of its proper divisors (242806026613).

1214030133035 is an equidigital number, since it uses as much as digits as its factorization.

1214030133035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 242806026612.

The product of its (nonzero) digits is 3240, while the sum is 26.

Adding to 1214030133035 its reverse (5303310304121), we get a palindrome (6517340437156).

The spelling of 1214030133035 in words is "one trillion, two hundred fourteen billion, thirty million, one hundred thirty-three thousand, thirty-five".