Base | Representation |
---|---|
bin | 10110100111010000… |
… | …11100101011100011 |
3 | 1011100002112211211012 |
4 | 23103220130223203 |
5 | 144330433433103 |
6 | 5324405411135 |
7 | 606565543241 |
oct | 132350345343 |
9 | 34302484735 |
10 | 12140530403 |
11 | 5170016201 |
12 | 2429a09aab |
13 | 11b62c9401 |
14 | 83255d791 |
15 | 4b0c7e2d8 |
hex | 2d3a1cae3 |
12140530403 has 4 divisors (see below), whose sum is σ = 12532160448. Its totient is φ = 11748900360.
The previous prime is 12140530393. The next prime is 12140530421. The reversal of 12140530403 is 30403504121.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30403504121 = 41 ⋅741548881.
It is a cyclic number.
It is not a de Polignac number, because 12140530403 - 28 = 12140530147 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12140532403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 195814976 + ... + 195815037.
It is an arithmetic number, because the mean of its divisors is an integer number (3133040112).
Almost surely, 212140530403 is an apocalyptic number.
12140530403 is a deficient number, since it is larger than the sum of its proper divisors (391630045).
12140530403 is an equidigital number, since it uses as much as digits as its factorization.
12140530403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 391630044.
The product of its (nonzero) digits is 1440, while the sum is 23.
The spelling of 12140530403 in words is "twelve billion, one hundred forty million, five hundred thirty thousand, four hundred three".
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