121413003403 has 4 divisors (see below), whose sum is σ = 121413712320. Its totient is φ = 121412294488.

The previous prime is 121413003401. The next prime is 121413003433. The reversal of 121413003403 is 304300314121.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 304300314121 = 41 ⋅7421958881.

It is a cyclic number.

It is not a de Polignac number, because 121413003403 - 2¹ = 121413003401 is a prime.

It is a super-2 number, since 2×121413003403² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (121413003401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79701 + ... + 499177.

It is an arithmetic number, because the mean of its divisors is an integer number (30353428080).

Almost surely, 2^121413003403 is an apocalyptic number.

121413003403 is a deficient number, since it is larger than the sum of its proper divisors (708917).

121413003403 is an equidigital number, since it uses as much as digits as its factorization.

121413003403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 708916.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 121413003403 its reverse (304300314121), we get a palindrome (425713317524).

The spelling of 121413003403 in words is "one hundred twenty-one billion, four hundred thirteen million, three thousand, four hundred three".