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12142113 = 34047371
BaseRepresentation
bin101110010100…
…011000100001
3211211212211220
4232110120201
511102021423
61112125253
7205130514
oct56243041
924755756
1012142113
116943605
124096829
1326918a9
141880d7b
1510ec9e3
hexb94621

12142113 has 4 divisors (see below), whose sum is σ = 16189488. Its totient is φ = 8094740.

The previous prime is 12142103. The next prime is 12142129. The reversal of 12142113 is 31124121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12142113 - 29 = 12141601 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12142092 and 12142101.

It is not an unprimeable number, because it can be changed into a prime (12142103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2023683 + ... + 2023688.

It is an arithmetic number, because the mean of its divisors is an integer number (4047372).

Almost surely, 212142113 is an apocalyptic number.

It is an amenable number.

12142113 is a deficient number, since it is larger than the sum of its proper divisors (4047375).

12142113 is an equidigital number, since it uses as much as digits as its factorization.

12142113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4047374.

The product of its digits is 48, while the sum is 15.

The square root of 12142113 is about 3484.5534864599. The cubic root of 12142113 is about 229.8430750618.

Adding to 12142113 its reverse (31124121), we get a palindrome (43266234).

The spelling of 12142113 in words is "twelve million, one hundred forty-two thousand, one hundred thirteen".

Divisors: 1 3 4047371 12142113