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121421201403 = 383487635347
BaseRepresentation
bin111000100010101000…
…1000111111111111011
3102121102001102010022110
41301011101013333323
53442132311421103
6131440301423403
711525634116505
oct1610521077773
9377361363273
10121421201403
1147549114837
121b64786ab63
13b5b077a048
145c3bdb6d75
153259b37403
hex1c45447ffb

121421201403 has 8 divisors (see below), whose sum is σ = 163845476928. Its totient is φ = 79972196744.

The previous prime is 121421201351. The next prime is 121421201471. The reversal of 121421201403 is 304102124121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 121421201403 - 213 = 121421193211 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 121421201403.

It is not an unprimeable number, because it can be changed into a prime (121421201003) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 243817425 + ... + 243817922.

It is an arithmetic number, because the mean of its divisors is an integer number (20480684616).

Almost surely, 2121421201403 is an apocalyptic number.

121421201403 is a deficient number, since it is larger than the sum of its proper divisors (42424275525).

121421201403 is an equidigital number, since it uses as much as digits as its factorization.

121421201403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 487635433.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 121421201403 its reverse (304102124121), we get a palindrome (425523325524).

The spelling of 121421201403 in words is "one hundred twenty-one billion, four hundred twenty-one million, two hundred one thousand, four hundred three".

Divisors: 1 3 83 249 487635347 1462906041 40473733801 121421201403