Base | Representation |
---|---|
bin | 10001101010110100101… |
… | …011010010000010000001 |
3 | 11022002002112010122121111 |
4 | 101222310223102002001 |
5 | 124343201234204101 |
6 | 2325445025323321 |
7 | 153503206620460 |
oct | 21526453220201 |
9 | 4262075118544 |
10 | 1214212022401 |
11 | 428a43039954 |
12 | 1773a5196541 |
13 | 8a665b00111 |
14 | 42aa7c329d7 |
15 | 218b7750251 |
hex | 11ab4ad2081 |
1214212022401 has 4 divisors (see below), whose sum is σ = 1387670882752. Its totient is φ = 1040753162052.
The previous prime is 1214212022389. The next prime is 1214212022431. The reversal of 1214212022401 is 1042202124121.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1214212022401 - 25 = 1214212022369 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1214212022431) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 86729430165 + ... + 86729430178.
It is an arithmetic number, because the mean of its divisors is an integer number (346917720688).
Almost surely, 21214212022401 is an apocalyptic number.
It is an amenable number.
1214212022401 is a deficient number, since it is larger than the sum of its proper divisors (173458860351).
1214212022401 is an equidigital number, since it uses as much as digits as its factorization.
1214212022401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 173458860350.
The product of its (nonzero) digits is 512, while the sum is 22.
Adding to 1214212022401 its reverse (1042202124121), we get a palindrome (2256414146522).
The spelling of 1214212022401 in words is "one trillion, two hundred fourteen billion, two hundred twelve million, twenty-two thousand, four hundred one".
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