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12142330113 = 34198718131
BaseRepresentation
bin10110100111011110…
…10100000100000001
31011100012221021120010
423103233110010001
5144331414030423
65324512135133
7606620050224
oct132357240401
934305837503
1012142330113
115171035371
12242a5374a9
1311b67a9624
148328ab5bb
154b0ed7693
hex2d3bd4101

12142330113 has 8 divisors (see below), whose sum is σ = 16584646176. Its totient is φ = 7897450400.

The previous prime is 12142330111. The next prime is 12142330163. The reversal of 12142330113 is 31103324121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12142330113 - 21 = 12142330111 is a prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 12142330113.

It is not an unprimeable number, because it can be changed into a prime (12142330111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 49358943 + ... + 49359188.

It is an arithmetic number, because the mean of its divisors is an integer number (2073080772).

Almost surely, 212142330113 is an apocalyptic number.

It is an amenable number.

12142330113 is a deficient number, since it is larger than the sum of its proper divisors (4442316063).

12142330113 is an equidigital number, since it uses as much as digits as its factorization.

12142330113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 98718175.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 12142330113 its reverse (31103324121), we get a palindrome (43245654234).

The spelling of 12142330113 in words is "twelve billion, one hundred forty-two million, three hundred thirty thousand, one hundred thirteen".

Divisors: 1 3 41 123 98718131 296154393 4047443371 12142330113