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121431502435 = 5177079201809
BaseRepresentation
bin111000100010111100…
…0011010111001100011
3102121102202210110200011
41301011320122321203
53442142431034220
6131441310305351
711526120511615
oct1610570327143
9377382713604
10121431502435
1147553a10091
121b64b1b8257
13b5b2945929
145c3d4d8db5
15325a9be65a
hex1c45e1ae63

121431502435 has 16 divisors (see below), whose sum is σ = 154311998400. Its totient is φ = 91417409536.

The previous prime is 121431502399. The next prime is 121431502441. The reversal of 121431502435 is 534205134121.

It is a cyclic number.

It is not a de Polignac number, because 121431502435 - 29 = 121431501923 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 121431502397 and 121431502406.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 500811 + ... + 702619.

It is an arithmetic number, because the mean of its divisors is an integer number (9644499900).

Almost surely, 2121431502435 is an apocalyptic number.

121431502435 is a deficient number, since it is larger than the sum of its proper divisors (32880495965).

121431502435 is a wasteful number, since it uses less digits than its factorization.

121431502435 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 208910.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 121431502435 its reverse (534205134121), we get a palindrome (655636636556).

The spelling of 121431502435 in words is "one hundred twenty-one billion, four hundred thirty-one million, five hundred two thousand, four hundred thirty-five".

Divisors: 1 5 17 85 7079 35395 120343 201809 601715 1009045 3430753 17153765 1428605911 7143029555 24286300487 121431502435