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1214317412353 = 5651214885403
BaseRepresentation
bin10001101010111010111…
…101010100000000000001
311022002100212110000110001
4101222322331110000001
5124343410224143403
62325503312240001
7153505626462013
oct21527275240001
94262325400401
101214317412353
11428a97581991
12177414540001
138a6818b0036
1442ab7c281b3
15218c1b1bc1d
hex11abaf54001

1214317412353 has 4 divisors (see below), whose sum is σ = 1214532303408. Its totient is φ = 1214102521300.

The previous prime is 1214317412257. The next prime is 1214317412369. The reversal of 1214317412353 is 3532147134121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1214317412353 - 233 = 1205727477761 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1214317412393) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 107437051 + ... + 107448352.

It is an arithmetic number, because the mean of its divisors is an integer number (303633075852).

Almost surely, 21214317412353 is an apocalyptic number.

It is an amenable number.

1214317412353 is a deficient number, since it is larger than the sum of its proper divisors (214891055).

1214317412353 is an equidigital number, since it uses as much as digits as its factorization.

1214317412353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 214891054.

The product of its digits is 60480, while the sum is 37.

The spelling of 1214317412353 in words is "one trillion, two hundred fourteen billion, three hundred seventeen million, four hundred twelve thousand, three hundred fifty-three".

Divisors: 1 5651 214885403 1214317412353