12143204113 has 4 divisors (see below), whose sum is σ = 12145339828. Its totient is φ = 12141068400.

The previous prime is 12143204089. The next prime is 12143204119. The reversal of 12143204113 is 31140234121.

12143204113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31140234121 = 7643 ⋅4074347.

It can be written as a sum of positive squares in 2 ways, for example, as 9563275264 + 2579928849 = 97792^2 + 50793^2 .

It is a cyclic number.

It is not a de Polignac number, because 12143204113 - 2²¹ = 12141106961 is a prime.

It is a super-2 number, since 2×12143204113² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12143204119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1059306 + ... + 1070707.

It is an arithmetic number, because the mean of its divisors is an integer number (3036334957).

Almost surely, 2^12143204113 is an apocalyptic number.

It is an amenable number.

12143204113 is a deficient number, since it is larger than the sum of its proper divisors (2135715).

12143204113 is an equidigital number, since it uses as much as digits as its factorization.

12143204113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2135714.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 12143204113 its reverse (31140234121), we get a palindrome (43283438234).

The spelling of 12143204113 in words is "twelve billion, one hundred forty-three million, two hundred four thousand, one hundred thirteen".