121433120401 has 4 divisors (see below), whose sum is σ = 126712821312. Its totient is φ = 116153419492.

The previous prime is 121433120357. The next prime is 121433120437. The reversal of 121433120401 is 104021334121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 121433120401 - 2²⁹ = 120896249489 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (121433120491) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2639850421 + ... + 2639850466.

It is an arithmetic number, because the mean of its divisors is an integer number (31678205328).

Almost surely, 2^121433120401 is an apocalyptic number.

It is an amenable number.

121433120401 is a deficient number, since it is larger than the sum of its proper divisors (5279700911).

121433120401 is an equidigital number, since it uses as much as digits as its factorization.

121433120401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5279700910.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 121433120401 its reverse (104021334121), we get a palindrome (225454454522).

The spelling of 121433120401 in words is "one hundred twenty-one billion, four hundred thirty-three million, one hundred twenty thousand, four hundred one".