12143400015035 has 4 divisors (see below), whose sum is σ = 14572080018048. Its totient is φ = 9714720012024.

The previous prime is 12143400014957. The next prime is 12143400015067. The reversal of 12143400015035 is 53051000434121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12143400015035 - 2²⁰ = 12143398966459 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12143400014989 and 12143400015007.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1214340001499 + ... + 1214340001508.

It is an arithmetic number, because the mean of its divisors is an integer number (3643020004512).

Almost surely, 2^{12143400015035} is an apocalyptic number.

12143400015035 is a deficient number, since it is larger than the sum of its proper divisors (2428680003013).

12143400015035 is an equidigital number, since it uses as much as digits as its factorization.

12143400015035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2428680003012.

The product of its (nonzero) digits is 7200, while the sum is 29.

Adding to 12143400015035 its reverse (53051000434121), we get a palindrome (65194400449156).

The spelling of 12143400015035 in words is "twelve trillion, one hundred forty-three billion, four hundred million, fifteen thousand, thirty-five".