Base | Representation |
---|---|
bin | 10110100111100110… |
… | …11001100000101011 |
3 | 1011100021221200112201 |
4 | 23103303121200223 |
5 | 144332202313003 |
6 | 5324551121031 |
7 | 606632130316 |
oct | 132363314053 |
9 | 34307850481 |
10 | 12143401003 |
11 | 51716a69a8 |
12 | 242a973177 |
13 | 11b6a92ba6 |
14 | 832aa997d |
15 | 4b1149b1d |
hex | 2d3cd982b |
12143401003 has 16 divisors (see below), whose sum is σ = 12684625920. Its totient is φ = 11612088000.
The previous prime is 12143400989. The next prime is 12143401009. The reversal of 12143401003 is 30010434121.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12143401003 is a prime.
It is a super-2 number, since 2×121434010032 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12143401009) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1352178 + ... + 1361128.
It is an arithmetic number, because the mean of its divisors is an integer number (792789120).
Almost surely, 212143401003 is an apocalyptic number.
12143401003 is a deficient number, since it is larger than the sum of its proper divisors (541224917).
12143401003 is a wasteful number, since it uses less digits than its factorization.
12143401003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9498.
The product of its (nonzero) digits is 288, while the sum is 19.
Adding to 12143401003 its reverse (30010434121), we get a palindrome (42153835124).
The spelling of 12143401003 in words is "twelve billion, one hundred forty-three million, four hundred one thousand, three".
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