Base | Representation |
---|---|
bin | 10001101010111100100… |
… | …000000101001101000011 |
3 | 11022002102200011110010001 |
4 | 101222330200011031003 |
5 | 124343433341212003 |
6 | 2325510035220431 |
7 | 153506362526614 |
oct | 21527440051503 |
9 | 4262380143101 |
10 | 1214343304003 |
11 | 429000156745 |
12 | 177421147717 |
13 | 8a68707703b |
14 | 42abb447c0b |
15 | 218c403361d |
hex | 11abc805343 |
1214343304003 has 8 divisors (see below), whose sum is σ = 1285786046880. Its totient is φ = 1142901759360.
The previous prime is 1214343303991. The next prime is 1214343304033. The reversal of 1214343304003 is 3004033434121.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1214343304003 - 29 = 1214343303491 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1214343304033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2575333 + ... + 3010153.
It is an arithmetic number, because the mean of its divisors is an integer number (160723255860).
Almost surely, 21214343304003 is an apocalyptic number.
1214343304003 is a deficient number, since it is larger than the sum of its proper divisors (71442742877).
1214343304003 is a wasteful number, since it uses less digits than its factorization.
1214343304003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 599117.
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 1214343304003 its reverse (3004033434121), we get a palindrome (4218376738124).
The spelling of 1214343304003 in words is "one trillion, two hundred fourteen billion, three hundred forty-three million, three hundred four thousand, three".
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