Base | Representation |
---|---|
bin | 111000100011000011… |
… | …0100110100001001011 |
3 | 102121110000210100021100 |
4 | 1301012012212201023 |
5 | 3442144404020133 |
6 | 131441522112443 |
7 | 11526164224254 |
oct | 1610606464113 |
9 | 377400710240 |
10 | 121435220043 |
11 | 4755601a195 |
12 | 1b6504ab723 |
13 | b5b3647ab7 |
14 | 5c3dbc5b2b |
15 | 325aea5e13 |
hex | 1c461a684b |
121435220043 has 6 divisors (see below), whose sum is σ = 175406428964. Its totient is φ = 80956813356.
The previous prime is 121435220041. The next prime is 121435220047. The reversal of 121435220043 is 340022534121.
121435220043 is a `hidden beast` number, since 1 + 2 + 1 + 435 + 220 + 0 + 4 + 3 = 666.
It is not a de Polignac number, because 121435220043 - 21 = 121435220041 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 121435219989 and 121435220016.
It is not an unprimeable number, because it can be changed into a prime (121435220041) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 6746401105 + ... + 6746401122.
Almost surely, 2121435220043 is an apocalyptic number.
121435220043 is a deficient number, since it is larger than the sum of its proper divisors (53971208921).
121435220043 is a wasteful number, since it uses less digits than its factorization.
121435220043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13492802233 (or 13492802230 counting only the distinct ones).
The product of its (nonzero) digits is 5760, while the sum is 27.
Adding to 121435220043 its reverse (340022534121), we get a palindrome (461457754164).
The spelling of 121435220043 in words is "one hundred twenty-one billion, four hundred thirty-five million, two hundred twenty thousand, forty-three".
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