Base | Representation |
---|---|
bin | 1011000010110110111011… |
… | …1110001100110001000011 |
3 | 1120222221002201121100112020 |
4 | 2300231232332030301003 |
5 | 3042430331443013041 |
6 | 41454430551532523 |
7 | 2362233025541241 |
oct | 260555676146103 |
9 | 46887081540466 |
10 | 12143734344771 |
11 | 39621464a6497 |
12 | 144165408a143 |
13 | 6a11c2b3bc33 |
14 | 2dda8d16b791 |
15 | 160d468de866 |
hex | b0b6ef8cc43 |
12143734344771 has 4 divisors (see below), whose sum is σ = 16191645793032. Its totient is φ = 8095822896512.
The previous prime is 12143734344769. The next prime is 12143734344787. The reversal of 12143734344771 is 17744343734121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12143734344771 - 21 = 12143734344769 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12143734344271) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2023955724126 + ... + 2023955724131.
It is an arithmetic number, because the mean of its divisors is an integer number (4047911448258).
Almost surely, 212143734344771 is an apocalyptic number.
12143734344771 is a deficient number, since it is larger than the sum of its proper divisors (4047911448261).
12143734344771 is an equidigital number, since it uses as much as digits as its factorization.
12143734344771 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4047911448260.
The product of its digits is 4741632, while the sum is 51.
The spelling of 12143734344771 in words is "twelve trillion, one hundred forty-three billion, seven hundred thirty-four million, three hundred forty-four thousand, seven hundred seventy-one".
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